Passing 2 D array to function

double f(double values[][4], int n);

int main() {
  double beans[3][4] = {
                         { 1.0,  2.0,  3.0,  4.0},
                         { 5.0,  6.0,  7.0,  8.0},
                         { 9.0, 10.0, 11.0, 12.0}
                       };

 printf(" %f\n",f(beans, sizeof beans/sizeof beans[0]));
 getch();
  return 0;
}

double f(double array[][4], int size) {
  double sum = 0.0;
  int i,j;
  for( i = 0 ; i < size ; i++)      
    for( j = 0 ; j < 4 ; j++)       
      sum += array[i][j];
     
  return sum;
}

Another method is you dynamically allocate array and than pass its pointer to the function.
#include
#include
#include
// Ref : http://www.eskimo.com/~scs/cclass/int/sx9b.html
void printArray(int **array, int m, int n)
{
     int i,j;
 for(i=0;i
   for( j=0;j
printf("%d\n",array[i][j]);

     printf("\n");
}
int main()
{
      int i,j,k=0, m=5, n=20;
      int **a=(int **)malloc(m*sizeof(int *));
      for(i=0;i
      for(i=0;i      //for(i=0;i
      printArray(a,m,n);
      system("PAUSE");
      return 0;
}